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23 Nov 2019

Sources A and B emit long-range radio waves of wavelength 450 m,with the phase of the emission from A ahead of that from source Bby 90°. The distance rA from A to a detector is greater than thecorresponding distance rB from B by 87 m. What is the magnitude ofthe phase difference at the detector in rad?

I dont know what im doing wrong?
I take x/?=phase difference /360 degrees
so the corresponding phase difference= 360*87/450 = 69.6degree
hence the phase difference at the detector= 90+69.6 =159.6degree.

then converting to rad, 159.6 (pi/180 deg) = 2.7855 rad but wileykeeps saying that this answer is wrong? please help.

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Nestor Rutherford
Nestor RutherfordLv2
22 Jan 2019

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