A crate of fruit with mass 35.0 kg and specific heat capacity 3650 J/kg K slides down a ramp inclined at 36.8 degrees below the horizontal. The ramp is 8.00 m long. a) If the crate was at rest at the top of the incline and has a speed of 2.50 m/s at the bottom, how much work was done on the crate by friction?

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A 3.50-kg crate starting at rest slides down a rough 6.80-m-long ramp, inclined at 25.0° below the horizontal. The magnitude of the force of friction between the crate and the ramp is 8.30 N.

(a) How much work is done on the crate by friction?
J

(b) What is the change in potential energy of the crate in sliding down the ramp?
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(c) What is the speed of the crate at the bottom of the incline?
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graytermite88

A Sliding Crate of Fruit

A crate of fruit with a mass of 30.5 kg and a specific heat capacity of 3550 J/(kg-K) slides 8.20 m down a ramp inclined at an angle of 39.1 degrees below the horizontal.

Part A

If the crate was at rest at the top of the incline and has a speed of 3.00 m/s at the bottom, how much work Wf was done on the crate by friction?

Use 9.81 m/s2 for the acceleration due to gravity and express your answer in joules.

Part B

If an amount of heat equal to the magnitude of the work done by friction is absorbed by the crate of fruit and the fruit reaches a uniform final temperature, what is its temperature change ?

lilaczebra939

A 40 N crate starting at rest slides down 6.0 m ramp inclined at 80 degrees with horizontal . Force of friction between crate and ramp is 6.0 N Find velocity of crate at bottom of incline.

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