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23 Nov 2019
The given explanation for solving the problem did not go into agreat deal of detail on deriving the 2nd equation: v^2=2ukgX. I'massuming that this equation is generated from an equation forconstant acceleration V^2= Vo^2 + 2a(X-Xo) and understanding thatthe sum of the horizontal (or vertical forces) is SumF=ma and theonly force acting on the mass is friction force, therefore,uk(m1+m2)g=(m1+m2)a and ukg=a.
My questions is this:
In the explanation, there seems to be an assumption that Vo is 0.Why can this assumption be made?
I'm probing because I've been following the explanation to answerthe question, and I continue to get it wrong.
Thank you,
SJ
The given explanation for solving the problem did not go into agreat deal of detail on deriving the 2nd equation: v^2=2ukgX. I'massuming that this equation is generated from an equation forconstant acceleration V^2= Vo^2 + 2a(X-Xo) and understanding thatthe sum of the horizontal (or vertical forces) is SumF=ma and theonly force acting on the mass is friction force, therefore,uk(m1+m2)g=(m1+m2)a and ukg=a.
My questions is this:
In the explanation, there seems to be an assumption that Vo is 0.Why can this assumption be made?
I'm probing because I've been following the explanation to answerthe question, and I continue to get it wrong.
Thank you,
SJ
