Consider an Earth-like planet hit by an asteroid. The planet hasmass Mp = 3.59 Ã 1023 kg and radius Rp = 6.08 Ã 106 m, and you mayapproximate it as a solid ball of uniform
density. It rotates on its axis once every T = 35 hr. The asteroidhas mass Ma =2.01 Ã 1017 kg and speed va = 26900 m/s (relative tothe planetâs center); its velocity vector points = 54? below theEastward horizontal. The impact happens at an equatorial location.First, calculate the planetâs angular momentum (relative to itsspin axis) before the impact.
Answer in units of kgm2/s.
Part B) Calculate the asteroidâs angular momentum relative to theplanetary axis.
Answer in units of kgm2/s.
Part C)The impact is totally inelastic â the asteroid is stuck inthe planetâs crust. But thanks to the asteroidâs angular momentum,the planet rotates faster after the impact than it didbefore.
By how many seconds has the collision shortened the planetary day?For simplicity, ignore the effect of the asteroidâs mass on theplanetâs moment of inertia
and assume Iafter = Ibefore planet .
Warning: At intermediate stages of this calculation, do not roundoff intermediate results and keep at least 7 significantdigits.
Answer in units of s.
Consider an Earth-like planet hit by an asteroid. The planet hasmass Mp = 3.59 Ã 1023 kg and radius Rp = 6.08 Ã 106 m, and you mayapproximate it as a solid ball of uniform
density. It rotates on its axis once every T = 35 hr. The asteroidhas mass Ma =2.01 Ã 1017 kg and speed va = 26900 m/s (relative tothe planetâs center); its velocity vector points = 54? below theEastward horizontal. The impact happens at an equatorial location.First, calculate the planetâs angular momentum (relative to itsspin axis) before the impact.
Answer in units of kgm2/s.
Part B) Calculate the asteroidâs angular momentum relative to theplanetary axis.
Answer in units of kgm2/s.
Part C)The impact is totally inelastic â the asteroid is stuck inthe planetâs crust. But thanks to the asteroidâs angular momentum,the planet rotates faster after the impact than it didbefore.
By how many seconds has the collision shortened the planetary day?For simplicity, ignore the effect of the asteroidâs mass on theplanetâs moment of inertia
and assume Iafter = Ibefore planet .
Warning: At intermediate stages of this calculation, do not roundoff intermediate results and keep at least 7 significantdigits.
Answer in units of s.