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23 Nov 2019

how do I calculate (?x)^2... I know ?x= (x - <x>)^1/2; so(?x)^2= (x - <x>)
<x> is an odd function so it is zero
so, <x^2> is left over
and, after the integration is solved check to see if normalizationis done and after this i'm stuck...

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