A block of mass m_1 = 1.30 kg moving at v_1 = 1.20 m/s undergoes acompletely inelastic collision with a stationary block of mass m_2= 0.700 kg. The blocks then move, stuck together, at speed v_2.After a short time, the two-block system collides inelasticallywith a third block, of mass m_3 = 2.60 kg, which is initially atrest. The three blocks then move, stuck together, with speed v_3.Assume that the blocks slide without friction.
ind \frac{v_2}{v_1}, the ratio of the velocity v_2 of the two-blocksystem after the first collision to the velocity v_1 of the blockof mass m_1 before the collision.
\frac{v_2}{v_1} =
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Part B
Find \frac{v_3}{v_1}, the ratio of the velocity v_3 of thethree-block system after the second collision to the velocity v_1of the block of mass m_1 before the collisions.
\frac{v_3}{v_1} =
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A block of mass m_1 = 1.30 kg moving at v_1 = 1.20 m/s undergoes acompletely inelastic collision with a stationary block of mass m_2= 0.700 kg. The blocks then move, stuck together, at speed v_2.After a short time, the two-block system collides inelasticallywith a third block, of mass m_3 = 2.60 kg, which is initially atrest. The three blocks then move, stuck together, with speed v_3.Assume that the blocks slide without friction.
ind \frac{v_2}{v_1}, the ratio of the velocity v_2 of the two-blocksystem after the first collision to the velocity v_1 of the blockof mass m_1 before the collision.
\frac{v_2}{v_1} =
submithintsshow answer
Part B
Find \frac{v_3}{v_1}, the ratio of the velocity v_3 of thethree-block system after the second collision to the velocity v_1of the block of mass m_1 before the collisions.
\frac{v_3}{v_1} =
submithintsshow answer
