Log in
Physics
1
answer
0
watching
87
views
23 Nov 2019

Two identical batteries, each with an emf of 18V and an internalresistance of 1 O, are wired in
parallel by connecting their positive terminals together andconnecting their negative terminals
together. The combination is then wired across a 4-O resistor. Thecurrent in each battery is:
A. 1.0A
B. 2.0A
C. 4.0A
D. 3.6A
E. 7.2A

Watch
1
answer
0
watching
87
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Nelly Stracke
Nelly StrackeLv2
22 Nov 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share

Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

An ideal voltmeter connected across a certain 9-V fresh battery reads 9.30 V, and an ideal ammeter briefly connected across the same battery reads 3.70 A. We say the battery has an open-circuit voltage of 9.30 V and a short-circuit current of 3.70 A. Model the battery as a source of emf ε in series with an internal resistance r. Determine both (a) ε and (b) r. An experimenter connects two of these identical batteries together as shown in the figure below. Find (c) the open-circuit voltage and (d) the short-circuit current of the pair of connected batteries. (e) The experimenter connects a 12.0-Ω resistor between the exposed terminals of the connected batteries Find the current in the resistor. (f) Find the power delivered to the resistor. (g) The experimenter connects a second identical resistor in parallel with the first. Find the power delivered to each resistor. (h) Because the same pair of batteries is connected across both resistors as was connected across the single resistor, why is the power in part (g) not the same as that in part (f)?

Two identical light bulbs are connected to identical batteries intwo different ways. In method A, the bulbs are connected inparallel, and the parallel combination is connected between the onebattery's terminals. In method B, the bulbs are connected inseries, and the series combination is connected between the otherbattery's terminals. What is the ratio of the power supplied by thebattery in method A to the power supplied in method B?

The answer is 4:1. Can someone please explain how this answer wasobtained? Thanks!

A potential difference of 200 V is applied to a series connectionof two capacitors, of capacitances C1 = 3.00 µF and capacitance C2= 8.00 µF.

(a) What is the charge q1 on capacitor 1?
C

(b) What is the potential difference V1 across capacitor 1?
V

(c) What is the charge q2 on capacitor 2?
C

(d) What is the potential difference V2 on capacitor 2?
V
The charged capacitors are then disconnected from each other andfrom the battery. Then the capacitors are reconnected with platesof the same signs wired together (the battery is not used).
(e) What now is q1?
C

(f) What is V1?
V

(g) What is q2?
C

(h) What is V2?
V
Suppose, instead, the capacitors charged in part (a) arereconnected with plates of opposite signs wired together.
(i) What now is q1?
C

(j) What is V1?
V

(k) What is q2?
C

(l) What is V2?
V

Weekly leaderboard

Home
Homework Help 3,900,000
Physics 110,000
Start filling in the gaps now
Log in