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23 Nov 2019

A 40 kg artillery shell was fired from a cannon with an initial speed of 84 m/s at a 45° angle above the ground. Unfortunately, the shell was poorly made and exploded into two pieces 4 s after it was launched. One piece was five times heavier than the other. The heavier piece landed 600 m from the cannon. How far from the cannon (in meters) did the lighter piece land? HINT: the range of an artillery shell is given by the equation (v^2* sin(theata))/g , where v0 is the initial speed of the shell and ? is the launch angle.

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Jean Keeling
Jean KeelingLv2
20 Feb 2019

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