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23 Nov 2019

On a day when the air temperature is 65°F, the wet-bulb reading ofa psychrometer is 61°F. Find the following measurement:

maximum moisture capacity of the air?

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

If a person breathes 10 liters per minute of air at 68degreesF and 50% relative humidity, how much water per day musttheinternal membranes supply to saturate the air at 98.6 degrees F?(Assume all the moisture is exhaled) If each gram of waterextracts580 calories as it is vaporized, how much daily heat lossinkilocalories (food calories) does this represent? (Saturationvaporpressure at 20 degrees C is 17.3 g/m cubed and 37 degrees C is44.0g/m cubed (grams per cubic meter).
Answer
Water per day: _________grams
Energy per day lost: _______

I have more information to a problem I asked about earlier. Icontinue to get an answer of 18 degrees Kelvin which is differentfrom an answer I received earlier. It is my fault since I did notgive the entire question previously.

Here is the question:
A garage (24ftx24ftx10ft) is illuminated by (6) 60W incandescentbulbs. It is estimated that 90% of the energy to an incandescentbulb is dissipated as heat. If the bulbs are on for 3 hours, howmuch would the temperature in the garage increase because of thelightbulbs (assuming no energy losses).
Information Given:

Formula Q=MCpDeltaT
Q is the amount of energy added (joules)
M is the mass of the fluid (kg)
Cp is the heat capacity of the fluid (joules/kg/K)
Delta T is the change in temperature (K or °C)

Number of Lightbulbs: 6
Power From Each Lightbulb (Joules/second): 60
Bulb % Power Loss as Heat: 90%
Amount of Time Bulbs in "On" Position (Hrs): 3
Time Bulbs On (Seconds): 10800
Garage Air Volume (ft3): 5760
Air Density (kg/m³): 1.2
Air Heat Capacity (Joules/kg/K): 1000


Three Hrs of Power from 1 Bulb (watts): ?
Three Hrs of Power All 6 Bulbs (watts): ?
Total Bulb Power Lost as Heat (joules/second): ?
Total Bulb Energy Lost as Heat (joules): ?
Garage Air Volume (m³): ?
Garage Air Mass (kg): ?
Temperature Change (K): ?

If a person breathes 10 liters per minute of air at 68 degrees Fand50% relative humidity, how much water per day must theinternalmembranes supply to saturate the air at 98.6 degrees F?(Assume allthe moisture is exhaled) If each gram of water extracts580calories as it is vaporized, how much daily heat lossinkilocalories(food calories) does this represent? (Saturationvaporpressure at 20 degrees C is 17.3 g/m3 and at 37degreesC is 44.0 g/m cubed.

Hint: 1/2 humidity, 1/2 saturation: inhale 17.3/2=8.65saturation

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