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23 Nov 2019
The acceleration of a particle is given by a(t)= - 1.95 m/s^2 +(2.94 m/ s^3 )t.
Find the initial velocity v such that the particle will have thesame x-coordinate at time t= 4.10 s as it had at t=0.
What will be the velocity at time t = 4.10 s?
The acceleration of a particle is given by a(t)= - 1.95 m/s^2 +(2.94 m/ s^3 )t.
Find the initial velocity v such that the particle will have thesame x-coordinate at time t= 4.10 s as it had at t=0.
What will be the velocity at time t = 4.10 s?
Irving HeathcoteLv2
25 Feb 2019
