Hello. I received help on this question but (c) was not correct andstill need help. I have included the answers to the (a) and (b) andsome comments on help with (c).
A startled armadillo leaps upward rising 0.542 m in the first 0.200s.
(a) What is its initial speed as it leaves the ground?
3.69 m/s
(b) What is its speed at the height of 0.542 m?
1.73 m/s
(c) How much higher does it go?
? m
Hint: Constant-acceleration equations, for vertical motion. Youknow the final velocity (at maximum height), the time to reachmaximum height, and the (downward) acceleration, and you want theinitial velocity. Next, you know the initial velocity, the time tothe tower top, and the acceleration, and you want the height of thetower.
Thank you.
Hello. I received help on this question but (c) was not correct andstill need help. I have included the answers to the (a) and (b) andsome comments on help with (c).
A startled armadillo leaps upward rising 0.542 m in the first 0.200s.
(a) What is its initial speed as it leaves the ground?
3.69 m/s
(b) What is its speed at the height of 0.542 m?
1.73 m/s
(c) How much higher does it go?
? m
Hint: Constant-acceleration equations, for vertical motion. Youknow the final velocity (at maximum height), the time to reachmaximum height, and the (downward) acceleration, and you want theinitial velocity. Next, you know the initial velocity, the time tothe tower top, and the acceleration, and you want the height of thetower.
Thank you.
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