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26 Nov 2019

An electron of mass 9.11×10^(-31) kg leaves one end of a TV picturetube with zero initial speed and travels in a straight line to theaccelerating grid, which is a distance 2.05 cm away. It reaches thegrid with a speed of 2.10×10^6 m/s. The accelerating force isconstant.

Find the acceleration (m/s^2)

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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An electron of mass 9.11×10-31 kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 1.35 cm away. It reaches the grid with a speed of 3.20×106 m/s. The accelerating force is constant.

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An electron of mass 9.11 multiplied by 10-31 kg has an initialspeed of 5.00 multiplied by 105 m/s. It travels in a straight line,and its speed increases to 6.00 multiplied by 105 m/s in a distanceof 2.00 cm.

(a) Assuming its acceleration is constant, determine the forceexerted on the electron.
_______ N (in the direction of motion)
(b) What is the ratio of this force to the weight of the electron,which we neglected?
_______

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