figured it out...

Trying to find an expressionforv_t,
Which is the Terminal Speed of the loop.

If F=ma, and v=at, then F/M=v/t, right?

So then the force on the loop would be the force ofthemagnetic field minus the force of gravity, correct?(F_m-F_g)

Where would i go from here?

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In a certain region of space near Earth's surface, a uniform horizontal magnetic field of magnitude B exists above a level defined to be y=0. Below y=0, the field abruptly becomes zero. A vertical square wire loop has resistivity ρ, mass density ρ_(m), diameter d, and side length l. It is initially at rest with its lower horizontal side at y=0 and is then allowed to fall under gravity, with its plane perpendicular to the direction of the magnetic field.

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chocolatehorse686

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(a) the magnitude of the induced emf in the loop during the time interval from to ,

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lilacleopard547

1) A flying pig (wings not shown) of mass m, supported from theceiling by a string, travels at speed v -- just the right speedthat it doesn't go up or down; it travels in a horizontal circle ina plane parallel to the ground.
c) On the pig at right, draw a force diagram showing the two forcesacting on the pig. Donât draw the components yet.
d) One force is diagonal and one force is vertical. Which do wechoose for an axis? We'll choose horizonal/vertical. Why not choosethe string and a line perpendicular to the string?
e) Given that we're choosing the radius and up/down line for ouraxis, which force needs to be resolved into components?
f) Using letters only, write the force equation for the up/downaxis in terms of FT, Î¸, m and g (Correct answer: FtCos(Î¸)=mg)
g) Using letters only, write the force equation for the radius axisin terms of FT, Î¸, m,v and r. (Correct answer:Ftsin(Î¸)=(mv^2/r)
h) Combine them into one equation using everybody's favorite trigidentity. (No, not sin(2Î¸) = 2sin(Î¸)cos(Î¸).) The equation shouldread: tan(Î¸) = v^2/rg