Question

Vertical height h₁ = 5.00cm

h₂=1.60cm

d = 6.00cm

To find the center ofmassspeedv on the plateau, we use the projectilemotion

equations.Withv_oy =0 (andusing“h” for h2) Eq. 4-22givesthetime-offlight as

t=√2h/g

Then Eq. 4-21 (squared,andusingd for the horizontal displacement) gives

v²=gd²/2h Now, tofindthe speed vp at pointP, we use energyconservationwith Eq. 11-5:

Mechanical Energy on the Plateau =MechanicalEnergyat P

1/2 mv²+1/2I_com ω²+mgh₁=1/2mv²_p+1/2I_comω²_p

Using item (f) ofTable10-2,Eq. 11-2, and our expression(above)v²=gd²/2h,we
obtain

gd²/2h+10gh₁/7=v_p²

which yields (using the values statedintheproblem) v_p = 1.34 m/s.