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26 Nov 2019

A person has far points 80.4 cm from the right eye and 120 cmfromthe left eye. Write a prescription for the powers of thecorrectivelenses.
right lens diopters
left lens diopters

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Elin Hessel
Elin HesselLv2
24 Aug 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A patient can't see objects closer than 32 cm and wishes to clearlysee objects that are20.4 cm from his eye.

(a) Is the patient nearsighted or farsighted?
1
farsighted nearsighted



(b) If the eye-lens distance is 1.92cm, what is the minimum objectdistance p from thelens?
2 cm

(c) What image position with respect to the lens will allowthepatient to see the object?
3 cm

(d) Is the image real or virtual? Is theimage distance qpositive or negative?
4
realimage distance is negative distanceis positive virtual image



(e) Calculate the required focal length.
5 cm

(f) Find the power of the lens in diopters.
6 diopters

(g) If a contact lens is to be prescribed instead, findp,q, and f, and the power of thelens.
p = 7 cm
q = 8 cm
f = 9 cm
P = 10 diopters

The near point of a person's eye is 59.0 cm. To see objects clearlyat a distanceof -24.0 cm, what should be thefocal length and powerof the appropriate corrective lens? (Neglectthe distance from thelens to the eye.)
f = cm
P = diopters

A person with a nearsighted eye has near and far points of16 cm and34 cm,respectively.

(a) Assuming a lens is placed 2.0 cm fromtheeye, what power must the lens have to correctthiscondition?
(b) Suppose contact lenses placed directly on the cornea are usedtocorrect the person's eye. What is the power of the lens requiredinthis case, and what is the new near point? Hint:Thecontact lens and the eyeglass lens require slightlydifferentpowers because they are at different distances from theeye.

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