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27 Nov 2019

Two identical pellet guns are fired simultaneously from the edge ofa cliff. These guns impart an initial speed of 38 m/s to eachpellet. Gun A is fired straight upward, with the pellet going upand then falling back down, eventually hitting the ground beneaththe cliff. Gun B is fired straight downward. In the absence of airresistance, how long after pellet B hits the ground does pellet Ahit the ground? (in sec)

I started by labeling knowns and unknowns:
VoA= 38 m/s
accelA= -9.8 m/s^2 (gravity)
timeA=?

VoB = -38 m/s
accelB=-9.8 m/s^2
timeB=?

Then wrote my equations of motion:
VA = VoA + accelA(timeA)
VB = VoB + accelB(timeB)

Is it safe to assume both VA and VB (velocities of A and Brespectively) are = 0?
(Since both pebbles hit the ground at this instant, their velocityis 0?)

Either way, I'm stuck trying to solve... Someone help please!

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Lelia Lubowitz
Lelia LubowitzLv2
15 Mar 2019

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