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27 Nov 2019

An electric field E = ( 2.40×105 N/C, right) causes the 2.0 g ballin the figure to hang at an angle. What is theta?

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Trinidad Tremblay
Trinidad TremblayLv2
17 Apr 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

An electric field \vec {E} = ( 2.50×105 {\rm N/C}, right) causesthe 2.0 {\rm g} ball in the figure to hang at an angle.
What is \theta ?

Three 1.0 nC charges are placed as shown in the figure. Each ofthese charges creates an electric field E at a point 3.0 cm infront of the middle charge.

http://session.masteringphysics.com/problemAsset/1071351/6/26.P66.jpg

1. What are the three fields vec E_1, vec E_2, and vec E_3 createdby the three charges? Write your answer for each as a vector incomponent form

2. Do you think that electric fields obey a principle ofsuperposition? That is, is there a "net field" at this point givenby vec E net = E_1 + E_2 + E_3? Use what you learned in thischapter and previously in our study of forces to argue why this isor is not true

http://session.masteringphysics.com/problemAsset/1071379/4/27.P28.jpg

 

 

 


a. E vector = .... N/C. Give your answer in component form. (Assume that -axis is horizontal and points to the right, and -axis points upward.) Express your answer in terms of the unit vectors i and j. Express your answer using two significant figures.

b. E= ... N/C. (Give your answer as a magnitude and angle measured from the positive x-axis.)

c. Theta= .... CW from the +x axis. (Express your answer using two significant figures.)
I have tried a couple of times but got wrong answers.

 

2. A dipole with a positive charge of 4μC and a negative chargeof -4μC is centered at the origin and oriented along the x axiswith the positive charge located to the right of the origin. Thecharge separation is 0.0010 m. Find the electric field strength atx=4 m, y = 0.0 m. The value of k is 9.0 × 109N∙m2/C2.)

a. 0.6 N/C
b. -0.6 N/C
c. 1.1 N/C
d. -1.1 N/C

 

Thanks in advance.

 

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