Force F = (4.0 N)i + (-3.0 N)k acts on a pebble with positionvector r = (0.40 m)j + (-0.8k m)k , relative to the origin. What isthe resulting torque acting on the pebble about a point withcoordinates (-8.0 m, 8.0 m, -2.0 m)? Answer as a vector. I know Ï =r - r₁ x F.

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Casey DurganLv2

9 May 2019

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Force F = (4.0 N)i + (-3.0 N)k acts on a pebble with positionvector r = (0.40 m)j + (-0.8k m)k , relative to the origin. What isthe resulting torque acting on the pebble about a point withcoordinates (-8.0 m, 8.0 m, -2.0 m)? Answer as a vector. I know Ï =r - r₁ x F.

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Physics: Principles with Applications

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Force F = (4.0 N)i + (-3.0 N)k acts on a pebble with positionvector r = (0.40 m)j + (-0.8k m)k , relative to the origin. What isthe resulting torque acting on the pebble about a point withcoordinates (-8.0 m, 8.0 m, -2.0 m)? Answer as a vector. I know Ï =r - r1 x F.

Unlock all answers

Related textbook solutions

Physics: Principles with Applications

Related questions

Weekly leaderboard

Force F = (4.0 N)i + (-3.0 N)k acts on a pebble with positionvector r = (0.40 m)j + (-0.8k m)k , relative to the origin. What isthe resulting torque acting on the pebble about a point withcoordinates (-8.0 m, 8.0 m, -2.0 m)? Answer as a vector. I know Ï =r - r₁ x F.