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27 Nov 2019

A particle of mass 0.000113 g and charge
71 mC moves in a region of space where the
electric field is uniform and is 3.9 N/C in the
x direction and zero in the y and z direction.
If the initial velocity of the particle is given
by vy = 2.9 × 10^5 m/s, vx = vz = 0, what is
the speed of the particle at 0.3 s?
Answer in units of m/s.

So far I had used A=Q/M to determine acceleration .017 C/1.13x10^-7KG , then plugged that into Vf=Vo+at Vf=2.9x10^5 m/s + Ax(.3)s ...Ikeep getting the wrong answer, does it have something to do withneeding an x and y componant to the velocity and acceleration?please help me figure this out

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Bunny Greenfelder
Bunny GreenfelderLv2
19 Aug 2019

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