The figure below shows a circuit diagram. (R1 = 1490 , R2 = 580 ,?V = 21.5 V) (a) Determine the current. (b) Determine the potentialof wire A relative to ground. V

(c) Determine the voltage drop across the 1490 resistor.

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Four resistors are arranged as shown in figure a, where R1 = 1.1 O,R2 = 2.2 O, R3 = 2.8 O, and R4 = 3.9 O.Because the current in theequivalent resistor is 0.600 A, the current in each resistor of theoriginal circuit must also be 0.600 A. Find the voltage drop acrosseach resistor.
?V1.1 O = V

?V2.2 O = V

?V2.8 O = V

?V3.9 O = V

http://loncapa2.fsu.edu/enc/60/3bc8d2090c30c7fb22651e043c4a13cd8a3daa787d2b3efabda2a1ca7836bb2476235c259958b93c4662e9f74169f07666b203db5ee3600f1b7bf347ff750199454c7140e39f8fbae86104cf0373c490.gif

1) Calculate the current in the circuit of the figure below. AssumeV = 12.00 V, R1 = 7.50 ohms, R2 = 13.3 ohms and r = 2.10ohms.

ANSWER: I simply used V=IR and solved for I adding my resistancesin series and got I = 5.2E-1 A

2) Calculate the terminal voltage of the battery.

ANSWER: I DON'T KNOW WHAT TERMINAL VOLTAGE IS!

3) Calculate the magnitude of the voltage drop across R2.

ANSWER: ?

4) Calculate the magnitude of the voltage drop across R1.

ANSWER: ?

Consider the circuit shown on the attache figure, where E = 10 V, R1 =5.0Ω,R2 =3.4Ω,R3 =5.0Ω,R4 =4.0Ω,R5 =7.5Ω,andR6 = 2.0 Ω.

a) Find the equivalent resistance of the circuit.
b) Determine the current across each resistor.
c) Determine the power dissipated across each resistor