A 5.0-kg crate is on an incline that makes an angle 30degrees with the horizontal. If the coefficent of static frictionis 0.5, the maximum force that can be applied parallel to the planewithout moving the crate is:
A) 0
B) 3.3 N
C) 30 N
D) 46 N
E) 55 N

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Please Help me How to solve this and explain pls, I'mreally bad at solving. Thank you

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-> / 30 D \<- | | | \ <- 150 D -> /
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| A | | B | | C | ~~~~~~~
~~~~~~~~ ~~~~~~~ ~~~~~~~~ | D |
~~~~~~~~

determine the normal force nc that the crate exerts on the wedge when the system is at rest.

The crate shown is held against wedge B by a spring. The spring is 96.0% of its original uncompressed length l=3.00 m, and the spring constant is given as k=1450 N/m. The coefficient of static friction at all contacting surfaces is =0.150. The mass of the crate is m=28.0 kg. The angle is =12.0deg. Neglect the mass of the wedge. Assume the crate only moves in the y-direction and that wedge A can not move. Determine the normal force Nc that the crate exerts on the wedge when the system is at rest. Determine the magnitude of the smallest horizontal force P that is necessary to begin moving the crate upward.