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The velocity of waves on a string is 95.0 m/s. If the frequency of standing waves is 485 Hz, how far apart are two adjacent nodes?

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Analyn Tolentino
Analyn TolentinoLv10
25 Sep 2020

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Two waves simultaneously present on a long string have a phase difference between two waves is so that a standing wave formed from their combination is described by

   

 (a) Despite the presence of the phase angle , is it still true that the nodes are one-half wavelength apart?  

1 a) A standing wave of frequency 5 hertz is set up on astring 2 meters long with nodes at both ends and in the center.Find the speed at which waves propagate on the string.

1. 2.5 m/s 2. 10m/s 3. 0.4 m/s 4.20 m/s 5. 5 m/s
b) ind the fundamental frequency of vibration of thestring.
1. 7.5 Hz 2. 5Hz 3. 1Hz 4. 10Hz 5. 2.5 Hz

A nylon guitar string has a linear density of 7.0 g/m and is undera tension of 155 N. The fixed supports are distance D = 90.0 cmapart. The string is oscillating in the standing wave pattern shownin Figure 16-39.

Fig. 16-39

(a) Calculate the speed of the traveling waves whose superpositiongives this standing wave.
1 m/s
(b) Calculate the wavelength of these traveling waves.
2 cm
(c) Calculate the frequency of these traveling waves.
3 Hz

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