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A particle has a charge of +1.5uc and moves from point a to point b, a distance of 0.20m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and at B is  

(a) Find the magnitude and direction of the electric force that acts on the particle.

(b) Find the magnitude and direction of the electric field that the particle experiences.

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Priyanka
PriyankaLv10
21 Mar 2021

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