An ice skater has a moment of inertia of 5.0 when her arms are outstretched. At this time she is spinning at 3 rps. If she pulls in her arms and decreases her moment of inertia to , how fast will she be spinning?

A) 7.5 rps B) 8.4 rps C) 2.0 rps D) 10 rps E) 3.3 rps

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Mohd TalibLv10

11 Jan 2021

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Related questions

a person sits on a freely spinning lab stool (no friction). when this person extends her arms,

Ques:

A person sits on a freely spinning lab stool that has no friction in its axle. When this person extends her arms:

A) Her moment of inertia increases and her angular speed decreases

B) Her moment of inertia decreases and her angular speed decreases

C) Her moment of inertia increases and her angular speed increases

D) Her moment of inertia increases and her angular speed remains the same

E) Her moment of inertia increases and her angular speed increases

periwinklerhinoceros273

A reasonable estimate of the moment of inertia of an ice skater spinning with her arms at her sides can be made by modeling most of her body as a uniform cylinder. Suppose the skater has a mass of 64kg . One eighth of that mass is in her arms, which are 60cm long and 20cm from the vertical axis about which she rotates. The rest of her mass is approximately in the form of a 20cm -radius cylinder.

(a) Calculate the angular momentum of an ice skater spinning at 6.00 re/s given his moment of inertia is 0.400kg-m² (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia if his angular velocity decreases to 1.25 rev/s. (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.00 rev/s. What average torque was exerted if this takes 15.0 s?

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