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A 1.0 kg block and a 2.0 kg block are pressed together on a horizontal frictionless surface with a compressed spring between them. They are not attached to the spring. After they are released and have both moved free of the spring.

A. the magnitude of the momentum of the heavier block will be greater than the magnitude of the momentum of the lighter block.
B. the lighter block will have more kinetic energy than the heavier block.
C. both blocks will both have the same amount of kinetic energy.
D. both blocks will have equal speeds.
E. the heavier block will have more kinetic energy than the lighter block

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Rishabh Jain
Rishabh JainLv6
1 Nov 2020

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A light spring of force constant 3.85N/m is compressed by 8.00 cmand held between a .250 kg block on the left and a .500 kg block onthe right. Both blocks are at rest on a horizontal surface. Theblocks are released simultaneously so that the spring tends to pushthem apart. What is the maximum velocity each block attains if thecoefficient of kinetic friction between each block and the surfaceis:

A) 0
B) .100
C) .463

Assume that the coefficient of static friction is larger than thatfor kinetic friction

Hint:

In the part where there is friction you know that ;

-fk.d= (Uf+Kf)- (Ui+Ki)

d= 0.08-x ; (0.08 being the compressed distance)

You have to get the frictions for the two blocks, you already knowthe force of the spring.
For the heavier block the force of the spring will be smaller thanthe friction fk, so the heavier block will stand still, and thefrictional force exerted by the floor change the momentum of thetwo blocks system. The light block will gain speed as long as thespring force is larger than the friction force, that is until thespring compresses and the magnitude of the spring force:
Fs= kx =fk (lighter spring)

A light spring of force constant 3.85N/m is compressed by 8.00 cmand held between a .250 kg block on the left and a .500 kg block onthe right. Both blocks are at rest on a horizontal surface. Theblocks are released simultaneously so that the spring tends to pushthem apart. What is the maximum velocity each block attains if thecoefficient of kinetic friction between each block and the surfaceis:

A) 0
B) .100
C) .463

Assume that the coefficient of static friction is larger than thatfor kinetic friction

Hint:

In the part where there is friction you know that ;

-fk.d= (Uf+Kf)- (Ui+Ki)

d= 0.08-x ; (0.08 being the compressed distance)

You have to get the frictions for the two blocks, you already knowthe force of the spring.
For the heavier block the force of the spring will be smaller thanthe friction fk, so the heavier block will stand still, and thefrictional force exerted by the floor change the momentum of thetwo blocks system. The light block will gain speed as long as thespring force is larger than the friction force, that is until thespring compresses and the magnitude of the spring force:
Fs= kx =fk (lighter spring)

Answers:

A) -.256 m/s and .128 m/s
b) .0642 m/s and 0
c) 0 and 0

A light spring with force constant 3.95 N/m is compressed by 7.68cm as it is held between a 0.263 kg block on the left and a 0.526kg block on the right, both resting on a horizontal surface. Thespring exerts a force on each block, tending to push them apart.The blocks are simultaneously released from rest. Find theacceleration with which each block starts to move, given that thecoefficient of kinetic friction between each block and the surfaceis the following values. (Let the coordinate system be positive tothe right and negative to the left. Be sure to include the sign toindicate the direction of the acceleration.)

(a) μ = 0

acceleration of heavier block:
acceleration of lighter block:

(b) μ = 0.010

acceleration of heavier block:
acceleration of lighter block:

(c) μ = 0.138

acceleration of heavier block:
acceleration of lighter block:

I would really like to see how this is set up more than anything. Iwould assumed finding the spring potential energy (I got 0.01165J)and setting the two equal to it somehow added together? Help wouldbe much appreciated!!

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