Ball B is stationary when it is hit by an identical ball A as shown in the figure, with . The pre-impact speed of ball A is v0 = 1.0 m/s. What is the post-impact velocity of the ball B if the COR of the collision is e = 1?
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A 4.3 kg ball with a velocity of 5.0 m/s in the +x-directioncollides head-on elastically with a stationary 2.1 kg ball. What isthe speed of the first ball after the collision?What is the direction of the velocity of the first ball after thecollision?What is the speed of the second ball after the collision?What is the direction of the velocity of the second ball after thecollision?
Ball A is released from rest. Itcollides with the stationary ball B with a velocity3.2 m/s; immediately after the collision ball A travels in the samedirection with velocity 2.3 m/s.Ball A has mass 0.26 kg; ball B has mass 0.07 kg.the velocity of ball B immediately after the collision is 3.34m/sthe maximum height reached by ball B?
Starting with an initial speed of 6.27 m/s at a height of 0.363 m, a 2.03-kg ball swings downward and strikes a 5.47-kg ball that is at rest, as the drawing shows. (a) Using the principle of conservation of mechanical energy, find the speed of the 2.03-kg ball just before impact. (b) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 2.03-kg ball just after the collision. (c) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 5.47-kg ball just after the collision. (d) How high does the 2.03-kg ball swing after the collision, ignoring air resistance? (e) How high does the 5.47-kg ball swing after the collision, ignoring air resistance?
