Log in
Physics
1
answer
0
watching
103
views

How do you find the magnitude of the acceleration of the particle?

Two forces, f1 = (3i+5j)n and F2 = (6i-2j)n, act on a particle of mass 3kg, where I and j are perpendicular unit vectors. The resultant of the two forces is F.

 

Watch
1
answer
0
watching
103
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Verified Answer
Manoj Pandey
Manoj PandeyLv10
26 Sep 2020

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
25 Nov 2020

Answer verification

This is a step by step verification of the answer by our certified expert.
Subscribe to our livestream channel for more helpful videos.
Subscribe
Share

Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Two forces, F1=(-5i -5j)N and F2=(-4i -8j)N, act on a particle of mass 2.30 kg that is initially at rest at coordinates (2.10m, -4.20m). What are the components of the particle's velocity at t=11.0s? In what direction is the particle moving at t=11.0s? What displacement does the particle undergo during the first 11.0s? What are the coordinates of the particle at t=11.0s?

Two forces are applied to a car in an effort to move it, where F1 =403 N and F2 = 388 N. (Assume up and to the right as positivedirections.) F1?= 10 degrees and F2?= 30 degrees.

A) What is the resultant of these two forces?
Magnitude= ? (N)
Direction= ? (Degrees)

B) If the car has a mass of 3,000 kg, what acceleration does ithave? Ignore friction. (m/s^2)

Two forces F1 and F2, act on the 7.00-kg block shown in the drawing, the magnitudes of the forces are F1 = 59.0 N and F2 = 33.0 N. What is the horizontal acceleration (magnitude and direction) of the block?

 

Weekly leaderboard

Home
Homework Help 3,900,000
Physics 110,000
Start filling in the gaps now
Log in