Log in
Physics
1
answer
0
watching
130
views

A ball is thrown upward from the top of an 80-foot cliff with an initial velocity of 64 feet per second. The position function is

s=−16t2+64t+80 where the time t is measured in seconds. Find the height, velocity, and acceleration of the ball at t = 2.

Watch
1
answer
0
watching
130
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Supratim Pal
Supratim PalLv10
22 Jan 2021

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share

Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Velocity and Acceleration: A ball is thrown vertically upward from ground level with an initial velocity of 96 feet per second. Use a(t) = –32 feet per second per second square as the acceleration due to gravity. (Neglect air resistance.)

a. How long will it take the ball to rise to its maximum height?

b. What is the maximum height?

c. After how many seconds is the velocity of the ball one-half the initial velocity?

If a ball is thrown vertically upward with a velocity of 80 ft/s, then its height after t seconds is s = 80t − 16t2.
  1. (a) What is the maximum height reached by the ball?
  2. (b) What is the velocity of the ball when it is 96 ft above the ground on its way up? On its way down?

 

A ball is thrown vertically upward from ground level with an initial velocity of 96 feet per second. Assume the acceleration of the ball is a(t)=-32 feet per second per second. (Neglect air resistance.)

(a) How long will it take the ball to rise to its maximum height? What is the maximum height?

(b) After how many seconds is the velocity of the ball one-half the initial velocity?

(c) What is the height of the ballwhen its velocity is one-half the initial velocity?

Weekly leaderboard

Home
Homework Help 3,900,000
Physics 110,000
Start filling in the gaps now
Log in