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The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50 ×104 V/m. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts. What is the potential 1.00 cm from that plate (and 3.00 cm from the other)?

 

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Priyanka
PriyankaLv10
6 Dec 2020

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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Two parallel conducting plates are separated by a distance d = 12.6 cm. Plate B, which is at a higher potential has a value of 620 V. The potential at x = 7.50 cm from the plate B is 61.3 V. See diagram below.

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