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Protons having a kinetic energy of 5.00 MeV (1 eV = 1.60 × 10−19 J) are moving in the positive x direction and enter a magnetic field B=0.0500kˆB→=0.050 0k^ T directed out of the plane of the page and extending from x = 0 to x = 1.00 m as shown in Figure P28.50. (a) Ignoring relativistic effects, find the angle α between the initial velocity vector of the proton beam and the velocity vector after the beam emerges from the field. (b) Calculate the y component of the protons’ momenta as they leave the magnetic field.

Chapter 28, Problem 50CP, Protons having a kinetic energy of 5.00 MeV (1 eV = 1.60  1019 J) are moving in the positive x

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Priyanka
PriyankaLv10
23 Nov 2020

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