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The driver of a speeding truck slams on the brakes and skids to a stop through a distance d. On another trial, the initial speed of the truck is half as large. What now will be the truck’s skidding distance? (a) 2d (b) 2⎯⎯√2d (c) d (d) d/2 (e) d/4

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Priyanka
PriyankaLv10
15 Nov 2020

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

1)In an experiment on stopping distance, a truck drives 60mph,then the brakes are put on hard, so that the truck's wheelslock,and the truck skids to a stop. When the truck is empty, ithas amass of 3000 kg, and it skids to a stop in 30 m. Whatdistance (inm) does the truck skid when it is loaded with a2,027-kg mass?(Ans: 3.00x10^1)
2) The terminal velocity of a 0.00008-kg drop is 1.5m/s.Assuming a drag force F_D = -bv, what is the value of theconstantb (in kg/s)? (Ans: 5.23x10^ -4)
3) The drag force on large objects moving through air ismorenearly F_D = -bv^2. For this quadratic dependence on v, what isthevalue of the constant b (in Ns^2/m^2) if a 79-kg sky diver hasaterminal velocity of 51 m/s? (Ans: 2.98*10^-1)

. Consider two cars, a 700kg Porsche and a 600kg Honda Civic. ThePorsche is speeding along at 40 m/s (mph) and the Civic is goinghalf the speed at 20 m/s. If the two cars brake to a stop with thesame constant acceleration, lets look at whether the amount of timerequired to come to a stop or the distance traveled prior tostopping is influenced by their initial velocity.

1. A car traveling 5m/s slams on its brakes, creating anacceleration of -2 m/s2. How far did the car travel after itapplied its brakes? __________

2. The same car traveling for 10m/s applies the same accelerationof -2 m/s2. How far did the car travel after it applied its brakes?__________


I am obviously using the formula wrong.. wouldn't it be d=at^2

A certain cable car is San Francisco can stop in 10 s when traveling at maximum speed. On one occasion, the driver sees a dog a distance d m in front of the car and slams on the brakes instantly. The car reaches the dog 7.50 s later, and the dog jumps off the track just in time. If the car travels 3.62 m beyond the position of the dog before coming to a stop, how far was the car from the dog? [Hint: You will need three equations.]

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