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What happens when a charged insulator is plated near an uncharged metallic object?

(a) They repel each other.

(b) They attract each other.

(c) They may attract or repel each other, depending on whether the charge on the insulator is positive or negative.

(d) They exert no electric force on each other.

(e) The charged insulator always spontaneously discharges.

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Anil Kumar G.
Anil Kumar G.Lv10
9 Nov 2020
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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

1.Two uncharged, conducting spheres, A and B, are held at rest oninsulating stands and are in contact. A positively charged rod isbrought near sphere A. While the rod is in place, the two spheresare separated. How will the spheres be charged, if at all, afterthey are separated?
Sphere A Sphere B
(a) positive positive
(b) positive negative
(c) negative positive
(d) negative negative
(e) zero zero

2. A charged conductor is brought near an uncharged insulator.Which one of the following statements is true?
(a) Both objects will repel each other.
(b) Both objects will attract each other.
(c) Neither object exerts an electrical force on the other.
(d) The objects will repel each other only if the conductor has anegative charge.
(e) The objects will attract each other only if the conductor has apositive charge.

3. An electron is moved from point A, where the electric potentialis VA = –240 V, to point B, where the electric potential is VB =–360 V. What is the change in the electric
potential energy?
(a) 1.92×10–17 J (b) 2.04×10–17 J (c) 5.75×10–17 J (d) 8.98×10–17 J(e) 1.05×10–16 J

4. A -2q charge is located a distance d to the right of a +4qcharge, along the x
axis. At which point (or points) along the axis does the electricfield go to zero? To
solve this problem, consider an observer at point P, which is anarbitrary distance x from the +4q charge. Find the value (orvalues) for x (in terms of the separation distance d) where thetotal electric field vanishes.
(a) The electric field is never zero in the vicinity of thesecharges.
(b) The electric field is zero at x = -0.328d.
(c) The electric field is zero at x = +4.22d.
(d) The electric field is zero at both x = -2.26d and x =+2.26d.
(e) The electric field is zero at x = +3.41d.

5. point A is a distance L away from a point charge Q. Point B is adistance 4L away from Q. What is the ratio of the electrostaticpotential at B to that at A, i.e., what is VB/VA?
(a) 1/16
(b) 1/9
(c) 1/4
(d) 1/3
(e) can not be determined without specifying Q and L

6. Which one of the following statements best explains why it ispossible to define an electric potential
in a region of space that contains an electric field?
(a) Work must be done to bring two positive charges closertogether.
(b) Like charges repel one another and unlike charges attract oneanother.
(c) A positive charge will gain kinetic energy as it approaches anegative charge.
(d) The work required to bring two charges together is independentof the path taken.
(e) A negative charge will gain kinetic energy as it moves awayfrom another negative charge.

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.6383 N when separated by 50 cm, center-to-center. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.1902 N. What were the initial charges on the spheres? Since one is negative and you cannot tell which is positive or negative, there are two solutions. Take the absolute value of the charges and enter the smaller value here.

Two identical conducting spheres, fixed in place, attract eachother with a force of 0.094 N when their center to centerseparation is 54.00 cm. The spheres are then connected by a thinconducting wire. When the wire is removed, the spheres have a netpositive charge and repel each other with an electrostatic force of0.045 N. What was the initial negative charge on one of thespheres, and what was the initial positive charge on theother?(Hint: Use charge conservation and solve for one of theinitial charges. You will end up with a quadratic equation. Thesolutions give you the positive and negative charges.)

Initial negative charge _______C.
Initial positive charge _______C.

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