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6 Oct 2020
The vector position of a 3.50-g particle moving in the XY plane varies in time according to it, r1= (3i + 3j)t + 2jt2, where t is in seconds and it is in centimeters. At the same time, the vector position of a 5.50 g particle varies as r2 = 3i — 2jt2 — 6jt. At t= 2.50 s,
determine
(a) the vector position of the center of mass of the system,
(b) the linear momentum of the system,
(c) the velocity of the center of mass,
(d) the acceleration of the center of mass, and
(e) the net force exerted on the two-particle system.
The vector position of a 3.50-g particle moving in the XY plane varies in time according to it, r1= (3i + 3j)t + 2jt2, where t is in seconds and it is in centimeters. At the same time, the vector position of a 5.50 g particle varies as r2 = 3i — 2jt2 — 6jt. At t= 2.50 s,
determine
(a) the vector position of the center of mass of the system,
(b) the linear momentum of the system,
(c) the velocity of the center of mass,
(d) the acceleration of the center of mass, and
(e) the net force exerted on the two-particle system.
Manoj PandeyLv10
11 Nov 2020
