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Bragg reflection results in a first-order maximum at 14.2 °. In this case, at what angle would the second-order maximum occur?
a. 7.1° b. 14.2° c. 28.4° d. 29.4°

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A beam of x-rays with a wavelength of 0.06 nm is incident on acrystal. The angle of deviation for the second order reflected beamis f2 = 55°. The experimental setup is shown schematically in thefigure below.

a) Find the spacing between the atomic planes in the crystalresponsible for the second order reflection.

d = nm

b) Find the angle of deviation, f1, for the first order reflectedbeam.

f1 = °

c) Find the number of Bragg reflections that can occur for thisinterplane spacing and x-ray wavelength.

Number of Bragg peaks =

d) Find the longest possible x-ray wavelength that will produce aBragg reflection.

X-ray wavelength = nm

Hi, I need help with the following question. Could you pleaseshowyour work so that I may better understand how the solutionwasachieved? Thanks!

Upper plane d Lower planeUsethe figure as a reference for problems (1) and(2)

(1)Potassium iodide has a crystalline structure with atomicplanesseparated by 0.353 nm. A monochromatic x-ray shows afirst-orderdiffraction maximum when the grazing angle is7.60°.
a) Calculate the x-ray wavelength
b) Assume now that the x-ray is observed at an incident angleof31.9°. Will constructive interference occur? (Defend yourargumentcalculatively)

(2) Assume 0.140 nm x-rays are diffracted on aninterplanarspacing of NaCl, which is 0.281 nm.

a) What is the predicted angle in the first-order?

b) What is the predicted angle in the second-order?

c) What is the maximum order for reflection? Why?


A diffraction grating produces a first-order maximum at an angle of 24.5 ∘. What is the angle of the second-order maximum? answer in degrees.

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