ENGG 2230 Lecture : FluidMechWhite5ech02part2b.pdf

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105 champagne 6 inches above the bottom: p. Then the force on the bottom end cap is vertical only (due to symmetry) and equals the force at section aa plus the weight of the champagne below aa: 2. 88 circular-arc tainter gate abc pivots about point o. For the position shown, determine (a) the hydrostatic force on the gate (per meter of width into the paper); and (b) its line of action. Solution: the force is based on vertical projection: horizontal hydrostatic. Cg vert (9790)(3)(6 1) 176220 n at 4 m below c. The vertical force is upward and equal to the weight of the missing water in the segment. Reference to a good handbook will give you the geometric properties of a circular segment, and you may compute that the segment area is. 3. 261 m2 and its centroid is 5. 5196 m from point o, or 0. 3235 m from vertical line ac, as shown in the figure.

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