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Number of mercury atom in flask = 3.77 We know: 1 mole = 6.022 = = (3.77)/(6.0...

For given reaction: At 25°C, ΔH = -199 kJ/mol, S = -4.1 J/mol.K T = 25°C = 298...

grayprairie-dog475

A flask of mercury contains <picture><source srcset="https://s3.amazonaws.com/prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/632369596078033/question/0.webp?img=ac789779080baca93b9accc4de3f2ef1" type="image/webp"><img src="https://s3.amazonaws.com/prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/632369596078033/question/0.png?img=e5fb635cbc817e4b52c3c6d3c561217e" data-mlang="latex" data-equation="3.77%20%5Ctimes%2010%5E%7B22%7D%5C%3B%20atoms"></picture> . How many moles of mercury are in the flask?

Ozone (OR) in the atmosphere can react with nitric oxide (NO) 
O2(g)+NO(g)- NO2(g)+O2(g)
Calculate the G for this reaction at 25C
(H=-199kJ/mol, S=-4.1 J/K.mol)

Integrate 1/(1+x2) for limit [0,1].

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