BIOL 2400 Study Guide - Midterm Guide: Regulatory Sequence, Coevolution, Chromosome

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Multiple choice/id: 3 from unit 3, 2 from unit 4, 2 from unit 5. Problem (numerical: 2 from unit 3, 0 from unit 4, 1 from unit 5. Short answer: 1 from unit 3, 4 from unit 4, 3 from unit 5. Bolded along diagonals is narrow-sense heritabilites of the populations (top is krumm and bottom is cera: look at bolded for stigma exsertion, higher heritability for krumm population, components of narrow-sense heritability (= va/vp = va/va+vd+vi+ve+vgxe) One reason in heritability is differ in ve component (effect of environment on phenotypes between the two populations is different) 1-t: as t increases, relative fitness decreases for a2a2 genotype, therefore equilibrium frequency goes down, equilibrium frequency of a2 allele = s/(s+t) & equilibrium frequency of a1 allele =t/(s+t) As t increases, the equilibrium frequency of a1 allele goes up, therefore, frequency of a2 allele must go down.

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