[CHEM 1050] - Midterm Exam Guide - Ultimate 23 pages long Study Guide!

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This is the beginning of midterm exam 2. Third law of entropy: s = 0 (at 0k) also, this is good to measure entropy levels of reactions. S*= [(2) (192. 5 j/k*mol)] [(1) (191. 5 j/k*mol) + (3) (130. 58 j/k*mol)] If g is negative when the reaction (forward/spontaneous reaction). G = 0 when the reaction is at equilibrium. G is positive when reaction is forward and is not spontaneous. You have h and s for making nh3. If it were not for s, all exothermic reactions would be spontaneous. S can go up or down, depending on the temperature of the reaction. Negative contribution to g increases the tendency of reaction to go as written. But if s is negative t s decreases the tendency of reaction to occur. So when h and t s are of opposite signs, relative importance of two terms will dictate if g negative or positive.

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