ECE 318- Midterm Exam Guide - Comprehensive Notes for the exam ( 187 pages long!)

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The bandpass signal is given by s(t) = g(t) cos(2 fct) Using the multiplication theorem for fourier transforms, the corresponding spectrum is given by. [ (f fc) + (f + fc)] = The spectrum of s(f ) is shown below for the case that g(t) is nrz line code with rectangular pulse. Figure 1: spectrum for bipolar nrz line code. Problem 2 (haykin 9. 11a): (a) for coherent bpsk, we have: For pe = 10 4, we nd q 1(10 4) = 3. 72 and thus, p2eb/n0 = 3. 72 which yields eb/n0 = Since n0/2 = 10 10, we obtain eb = 6. 92 n0 = 1. 38 10 9, which is transmit energy per bit. Since there are 106 bits per second, the average transmission power required is eb 106 = 1. 38 10 9. Problem 3 : the block diagrams are plotted in gures 2 and 3.