MATH137 Study Guide - Final Guide: Mean Value Theorem, Antiderivative
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MATH137 Full Course Notes
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whenever x > 1 (cid:90) x (cid:90) b a d dx f (t) dt = f (x), for x (a, b) f (x) dx = f (b) f (a: tan(sec 1(4)) = tan(x) = a. 15. (x2 2x + 1) = 4 (cid:19: a) lim x 3 (cid:18) x, lim x 1 x 1. 2: a) f(cid:48)(x) = exe 1, g(cid:48)(x) = sec(x sinh x) tan(x sinh x)(sinh x + x cosh x, h(cid:48)(x) = x2 sin x, evaluate the following integrals. (cid:19) (cid:18) x. 1 x e2y = (cid:18) 1 + x (cid:19) (cid:18) 1 + x. Since lim x a that if 0 < |x a| < , then |f (x) l| < |c|. Thus, whenever 0 < |x a| < , we have f (x) = l, we get that for any > 0, there exists a > 0 such. |cf (x) cl| = |c||f (x) l| < |c| .