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Find the area of the region bounded by y = sin2x and y = cos x from x = - pi / 4 to x = pi. Set up the integral and simplify. You do not need to solve. Sin 2x = cos x 2 Sin x cos x - cos x = 0 cos x (2 sin x - 1) = 0 cos x = 0 sin x = 1 / 2 pi/2, pi/6, 5 pi/6 sin 2(0) = 0 sin 2(pi / 4) = 1 cos x - sin 2x dx + sin 2x - cos x dx + finding local extrema, inflection points, intervals wh
Show transcribed image text Find the area of the region bounded by y = sin2x and y = cos x from x = - pi / 4 to x = pi. Set up the integral and simplify. You do not need to solve. Sin 2x = cos x 2 Sin x cos x - cos x = 0 cos x (2 sin x - 1) = 0 cos x = 0 sin x = 1 / 2 pi/2, pi/6, 5 pi/6 sin 2(0) = 0 sin 2(pi / 4) = 1 cos x - sin 2x dx + sin 2x - cos x dx + finding local extrema, inflection points, intervals wh