CHE 1302 Study Guide - Midterm Guide: Stoichiometry, Horse Length, Equilibrium Constant

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Solution: we are given a value of kc and are asked to convert this to a value of kp. Kp = kc (rt) n gas where ngas is the difference in the number of reactant and product moles of gas in the balanced equation. Here, we have 2 moles of product gas and 3 moles of reactant gas, therefore n = product moles reactant moles = 2 3 = 1. Hence, we can just plug in all the numbers: Kp = 2. 7 102 (0. 0821 l atm/mol k 960 k) 1. = 3. 4: when solid nh4hs is placed in a closed flask at 28 oc, the solid dissociates according to the equation: The total pressure of the equilibrium mixture is 0. 766 atm. Determine kp at this temperature: 0. 766, 0. 383 c) 0. 587 d) 0. 147, 1. 53. Solution: we must first write an equilibrium expression in terms of gas pressures. We must remember that pure solids and liquids do not appear in the expression.

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