NE STUD 180 Midterm: ne180-fa2000-mt2--soln

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8 Jan 2019
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Ti(r) = ti(0)(1 0. 92) = 2. 85 kev. 2. 09 107(mi/mp)1=2ti(ev )3=2 (cgs units) ln . = 2. 87 1017m(cid:255)3s(cid:255)1: a. n i = ni = 2 1020(1 0. 92) = 3. 8 1018m(cid:255)3. Ci = qb/mi = (1. 67 10(cid:255)19)(4)/(2. 5 1. 67 10(cid:255)27) = 1. 53293 108 s(cid:255)1. I (2. 0)(3. 8 1018)(2. 85 103)(1. 6 10(cid:255)19) (2. 5 1. 67 10(cid:255)27)(1. 53293 108)2(7. 5607 10(cid:255)3) Ti = 2(0. 9)/2ti(0) = 1. 35 104 ev m(cid:255)1. = 2. 16 10(cid:255)15 j m(cid:255)1 qi = (2. 16 10(cid:255)15)(4. 67 1016) = 100. 918w m(cid:255)2. P i cond = qi a = 43. 0 kw: b, c, d. Plasma resistance = r = 2 kr/a2 = 2. 66 10(cid:255)9 . P = i 2r = 265. 6 kw qe k = e k. 3. 44 105ti(ev )3=2 ln (cgs units) E k = (3. 2)(104)(1. 6 10(cid:255)19)(1. 965 1016) = 1. 1 1032m(cid:255)1 s(cid:255)1 k = (1. 1 1032)(104)(1. 6 10(cid:255)19)/1000 qe. = 1. 768 1014 w m(cid:255)2 f = = 6. 63 10(cid:255)10: a. fb = 108(5) (17. 6 106)(1. 6 10(cid:255)19)(6. 02 1023) = 2979. 3 g cm(cid:255)2: b. ne =

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