MATH 1230 Midterm: Math 124.02 Brown Test4 2

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31 Jan 2019
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Find y in terms of x and y. x3y 3xy3 = 3x + 4y + 5. In problems 2-6, nd the equation of the tangent line to the curve at the given point. + 2y2 = 1 2x + 4y at the point (2, 1). + (y + 1)2 + 5x at the point (1, 0). #4. (3x 2y)2 + x3 = y3 2x 4 at the point (1, 2). Xy + x3 = y3/2 y x at the point (1, 4). Find y for the curve at the point (1, 3). Find the points at which the curve x3y3 = x + y has a horizontal tangent. xy + 2y3 = x3 22y at the point (3, 1). #2. f (2) = 4 and f (2) = 7. Use a linear approximation to approximate f (1. 02). A linear approximation is used to approximate y = f (x) at the point (3, 1).

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