21127 Study Guide - Quiz Guide: Conditional Probability, Black Dice, Fair Coin
16 Dec 2015
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Conditional probability (1) consider the set s of all outcomes of rolling two dice, one of which is colored white and the other of which is colored black. We assume the dice are fair, so every outcome is equally likely. Thus, given any event x s, it follows that pr(x) = Find the following probabilities: (i) (ii) (iii) (iv) (v) (vi) (vii) (viii) Pr(c d) = pr(c) + pr(d) = 12 because c d = (we can"t have one number be both smaller and equal to another number). This makes sense because there are 15 possible outcomes in c and only 2 of them also have the property that the white die shows a 4: (4, 5) and (4, 6). 1 (ix) (x) (xi) (xii) (xiii) (xiv) (xv) This makes sense for the exact same reasons as the last problem: there are 15 outcomes in c and.
