MATH 1120 Quiz: MATH 1120 Cornell WARMUP2018 Quiz5 3 18Solutions

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31 Jan 2019
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Take ln : an for an = n n . 2 n + 1. lim x ln(n + 1) n2. Use exercise i, and the root/ratio test to nd all values of x for which the series. X n n + 1 xn converge absolutely. n=1 n. So absolutely convergent for |x| < 1 and divergent for |x| > 1. A series which is divergent, cannot be aboslutely convergent; if it were, the theorem absconvergent = convergent gives a contradiction. n .