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APPM 1235 Midterm: appm1235spring2018exam2_sol

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turquoisegnu128

31 Jan 2019

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Instructions: outside paper and electronic devices are not permitted. Unless indicated, answers with no supporting work may receive no credit. 2x3 x2 + 1 (c) f (x) = x 2 (x + 1)(x 2) Solution: (a) f (x) = x(x + 4) x(x + 1)(x 1) = va at x = 1 and x = 1 , and a hole at (0, 4) Furthermore, x = f (x) 0 and x = f (x) 0, so there is a horizontal asymptote at y = 0 (b) Therefore there is an oblique asymptote at y = 2x . There are no ha"s or va"s. (c) f (x) = (x 2) (x + 1)(x 2) because x = f (x) 0. Solution: (a) (b) (c) y = bax + 1 = c = 1. 5 = b + 1 = b = 4. 7 = 4a + 1 = a = 3 y = 4( 3.

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