MATH 1502 Midterm: MATH 1502 GT prepTest2A09sol
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Solutions for practice test ii for calculus ii, math 1502, september 21, 2009. This test is to be taken without calculators and notes of any sorts. For example, if you mean 2 do not write 1. 414 . Show your work, otherwise credit cannot be given. I: (25 points: (7 points) does the series ( 1)k. By the integral test we have to show the existence of the integral. 1 x log x dx =z log 2. It is conditionally convergent since it is an alternating series and the sequence. 1/(l log k) is monotonically decreasing to zero as k : (10 points) consider the series ( 1)k 2k (2k)! If yes, calculate the rst fe digits after the decimal point of this limit. Yes, it is alternating and if l denotes the limit we have that. If we pick n = 4 we nd that. Hence the rst ve digits of the limit are given by.
