MATH 2552 Midterm: MATH 2552 GT fa 2015

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15 Feb 2019
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This exam covers chapter 3, chapter 4, and parts of chapter 6 and part of chapter 8 of. The exam covers some material on numerics, rst order systems, and second order linear ode. Name and section: (cid:26) x = 3x 4y y = x + 3y. Solution: this system can be written as y (cid:19) (cid:18) x or simply. = (cid:18) 3x 4y x + 3y (cid:19) = (cid:18) 3 4. Name and section: (17 points) (3. 2. 21) give a rst order system which is equivalent to the single ode y + 3y . Solution: letting x1 = y be one unknown in our system, we de ne two more un- knowns by x2 = x : the equivalent rst order system is then. 1 and x3 = x or simply x x x x = . Name and section: (17 points) (3. 3. 11) solve the linear system of odes x = (cid:18) 2 1.