AS.030.103 Study Guide - Final Guide: Radio National, Bond Order, Silver Nitrate
***Check pic
Paramagnetic: at least one unpaired e-
Diamagnetic: all paired e-
Start with 2s because ???
Bonding –(antibonding/2)=bond order
Bond strength-higher equals tighter bond (shorter bond length)
Mag?
Bond Order
Bond Strength
Bond Length
Li2
Di
1
weak
Long
Be2
Di
0
Super weak
Longer
B2
Para
1
Weak
Long
C2
2
Stronger
Shorter
N2
3
Super strong
Super short
O2
Para
2
stronger
Shorter
F2
1
weak
Long
Ne2
0
Super weak
longer
[Pt(NH3)5Cl]Cl3 ®[Pt(NH3)5Cl]3+ + 3Cl-
Between [Pt(NH3)5Cl4] (0 ions, less conductive) and [Pt(NH3)5Cl]Cl3 (has more conductivity
because there are more ions formed in solution (4 ions once in solution, more conductive))
Step 1: break up the molecule as much as u can
*3Cl- are counter ions
# of ions in solution: 4
*Conductance:
*Ox state: +4 Pt4+ <-find how to calculate!!!
*Coordination #: 6 (# of NH3 and Cl/things attached to Pt)
*d e-: 10 (group number) – 4 (+ charge [if charge is -, add rather than subtract]) = 6
moles AgNO3: 3
Ag++Cl-®AgCl
Carbon monoxide
Isoelectronic:
NO+ has 5+6-1=10 e-
Answer: N2
NO- has 5+6+1=12 e-
Answer: O2
***check pic for hybridization
*diagonal means coming out of the board perpendicularly
*sp2,sp,sp2,sp3
Allenes have two planes that are perpendicular to each other
*calculation of steric numbers
*when drawing hybridization on the exam, must draw as done in class, must label hybrid
orbitals or else NO POINTS (if drawing sigma bonds, must write sigma!), draw axes!
Document Summary
Bond strength-higher equals tighter bond (shorter bond length) Between [pt(nh3)5cl4] (0 ions, less conductive) and [pt(nh3)5cl]cl3 (has more conductivity because there are more ions formed in solution (4 ions once in solution, more conductive)) Step 1: break up the molecule as much as u can. *ox state: +4 pt4+
